Simple Calculus Question: Differentiating Square Root Fraction

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nil1996
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Homework Statement



[itex]\sqrt{\frac{1-cos2x}{1+cos2x}}[/itex]
differentiate with respect to x

Homework Equations



none

The Attempt at a Solution



i have simplified it by substituting cos2x as 1-2sin2x and 2cos2x-1

I have got the answer as sec2x but my textbook says the ans is [itex]\frac{tanx}{|tanx|}[/itex]sec2x
why??

please help
 
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rock.freak667 said:
I don't see the need for your book to specify tanx/tanx in it.

it is tanx/|tanx|
the denominator is mod of tanx
 
nil1996 said:
it is tanx/|tanx|
the denominator is mod of tanx

Yes well the main point was that for x>0, |tanx| = tanx so it would cancel out to give you sec2x.

The only reason I can think of to specify something like that is if you accounted for taking the square root of the radical.

Meaning that your expression would simplify to √(tan2x) = ± tanx

and d/dx(± tanx) = ± sec2x
 
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