Solving a Linear Differential Equation with a Square Root Term

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SUMMARY

The discussion focuses on solving the linear differential equation dv/dt = -327/3500 - (41/105)(√6)(v²). The solution involves separating variables and integrating both sides, leading to the expression 1/(√(327/3500)) * arctan(v * √((41/105)(√6)/(327/3500))) + C = -t. A critical correction noted is the missing factor of √(105/41) on the left-hand side, which is essential for accuracy. Verifying the solution through differentiation is also emphasized as a crucial step.

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MrMumbleX
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Homework Statement


dv/dt = -327/3500 – (41/105)(square root of 6)(v2). Solve for v.


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The Attempt at a Solution


dv/[327/3500 + (41/105)(square root of 6)(v2)] = -dt
Then integrate both sides. 1/(square root of (327/3500)) * arctan(v * square root of ((41/105)(square root of 6)/(327/3500))) + c = -t?
 
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Almost right. You seem to be missing a factor of sqrt(105/41) on the lefthand side.

You can always check your answer by differentiating and seeing if you recover what you started with.
 

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