Integrating exponential functions

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Pingunoot
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How would you integrate something like xe(x^2) by using a substitution like u=x^2
 
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2x, but my problem is how will this help when you still have e raised to the power u
 
Do you know what's

[tex]\int e^{u}du[/tex]

?
 
elibj123 said:
Do you know what's

[tex]\int e^{u}du[/tex]

?

no this is what I am stuck on
 
Well, you know that integration is some sort of anti-derivative, and you know that a function of which derivative is e^x, is e^x it self. So it's safe to say that:

[tex]\int e^{u}du=e^{u}+C[/tex]
 
elibj123 said:
Well, you know that integration is some sort of anti-derivative, and you know that a function of which derivative is e^x, is e^x it self. So it's safe to say that:

[tex]\int e^{u}du=e^{u}+C[/tex]

Thanks for your help, that cleared things up.
 
just to clarify, du is 2x(dx), not just not 2x. I'm sure you already knew that though.