Integrating Intergration Problem: 1/x^3*sqrt(x^2-1)dx

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SUMMARY

The discussion focuses on evaluating the definite integral of the function 1/x^3 * sqrt(x^2 - 1) dx from sqrt(2) to 2. The user successfully applies trigonometric substitution for the sqrt(x^2 - 1) component, identifying it as inverse sec(x/1) dx. However, there is uncertainty regarding the integration of 1/x^3, where the user contemplates using the substitution u = x^2 to simplify the process. The final integration result for 1/x^3 is confirmed as -1/2(1/x^2).

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Homework Statement


i'm taking a defitinite integral from sqrt2 to 2 of the function 1/x^3*sqrt(x^2-1)dx.

Homework Equations





The Attempt at a Solution


I separated it into 1/x^3 and 1/sqrt(x^2-1). I have the second part using trig sub. as being inverse sec(x/1) dx. I believe i did this part correctly.

What I can't remember is that I make 1/x^3 to x^-3 and then integrate it that way with the final being -1/2(1/x^2)??
 
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Why don't try the substitution u = x^2?
 

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