Integrating Kinematics for Velocity from Acceleration: A Simplified Approach

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To derive velocity from acceleration, integration is necessary when acceleration is a function of time, as opposed to simply multiplying acceleration by time, which only applies to constant acceleration. The equation v = a(t) dt represents the infinitesimal change in velocity over an infinitesimal time interval. When integrating over a finite time, the total change in velocity, Δv, is obtained by summing small changes in velocity, dv. Understanding this integration process is crucial for grasping the relationship between varying acceleration and velocity. A theoretical foundation can enhance comprehension of these concepts.
yup790
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When you want to get velocity from accelleration i have been told you integrate.

Howver v=at and so surley you can just multiply each term in the accelleratin expression by t.

ie:
a=4-0.2t

Surley you can just:
v=(4-0.2t)t
v=4t-0.2t2
 
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The equation v=at is for the situation when the acceleration is a constant. If it is a function of t, you have to integrate. In that case the corresponding equation is dv=a(t)dt, which gives the infinitesimal change in velocity, dv during infinitesimal time interval dt when the acceleration function a(t) is known. When integrating over a finite time interval, you effectively add a large number of small velocity changes dv to get the total change in velocity, Δv.
 
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Thank you. Is there any proof for this. I learn better when I understand the theory behind a topic.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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