Integrating Misc Integral with \int \frac{x}{\sqrt{3-x^4}}dx

[nameVoid]

<br /> \int \frac{x}{\sqrt{3-x^4}}dx<br />
<br /> u=x^2<br />
<br /> du=2xdx<br />
<br /> \frac{1}{2}\int\frac{du}{\sqrt{3-u^2}}<br />
<br /> u=\sqrt{3}sinT<br />
<br /> du=\sqrt{3}cosTdT<br />
<br /> \frac{1}{2}\int \frac{\sqrt{3}cosT}{\sqrt{3}cosT}dT<br /> <br />
<br /> \frac{x}{2}+C<br />

 

[Dick]

Not x/2+C. T/2+C.

 

[synapsis]

You need not do the second u-substitution. Use an integral table to solve it once you have done the first u-substitution. You can google 'integral table' to find one if you don't have one in your book.