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Integrating question but withe error

  1. Sep 8, 2014 #1
    1. The problem statement, all variables and given/known data

    Calculate the integral: ∫2x/(x2−11x+30) dx

    2. The attempt at a solution

    I factored and got A/(x-6) + B/(x-5) = 2x/(x2−11x+30)

    Then I isolated and found A = 12 and B = -10

    Then, after setting up the integral again, got 12ln(x-6) - 10ln(x-5) + C

    Unfortunately this is not the answer and I'm not exactly sure if there is an error in my calculation or steps itself. Any thoughts on where I went wrong?
     
  2. jcsd
  3. Sep 8, 2014 #2

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    You didn't go wrong, the answer is basically correct. Possibly they want you to put in the absolute values the usually use with log integrals?
     
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