Integrating question but withe error

  • Thread starter MathewsMD
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  • #1
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Homework Statement



Calculate the integral: ∫2x/(x2−11x+30) dx

2. The attempt at a solution

I factored and got A/(x-6) + B/(x-5) = 2x/(x2−11x+30)

Then I isolated and found A = 12 and B = -10

Then, after setting up the integral again, got 12ln(x-6) - 10ln(x-5) + C

Unfortunately this is not the answer and I'm not exactly sure if there is an error in my calculation or steps itself. Any thoughts on where I went wrong?
 

Answers and Replies

  • #2
Dick
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Homework Statement



Calculate the integral: ∫2x/(x2−11x+30) dx

2. The attempt at a solution

I factored and got A/(x-6) + B/(x-5) = 2x/(x2−11x+30)

Then I isolated and found A = 12 and B = -10

Then, after setting up the integral again, got 12ln(x-6) - 10ln(x-5) + C

Unfortunately this is not the answer and I'm not exactly sure if there is an error in my calculation or steps itself. Any thoughts on where I went wrong?

You didn't go wrong, the answer is basically correct. Possibly they want you to put in the absolute values the usually use with log integrals?
 

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