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Integrating question but withe error

  1. Sep 8, 2014 #1
    1. The problem statement, all variables and given/known data

    Calculate the integral: ∫2x/(x2−11x+30) dx

    2. The attempt at a solution

    I factored and got A/(x-6) + B/(x-5) = 2x/(x2−11x+30)

    Then I isolated and found A = 12 and B = -10

    Then, after setting up the integral again, got 12ln(x-6) - 10ln(x-5) + C

    Unfortunately this is not the answer and I'm not exactly sure if there is an error in my calculation or steps itself. Any thoughts on where I went wrong?
  2. jcsd
  3. Sep 8, 2014 #2


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    Science Advisor
    Homework Helper

    You didn't go wrong, the answer is basically correct. Possibly they want you to put in the absolute values the usually use with log integrals?
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