Calculate the integral: ∫2x/(x2−11x+30) dx
2. The attempt at a solution
I factored and got A/(x-6) + B/(x-5) = 2x/(x2−11x+30)
Then I isolated and found A = 12 and B = -10
Then, after setting up the integral again, got 12ln(x-6) - 10ln(x-5) + C
Unfortunately this is not the answer and I'm not exactly sure if there is an error in my calculation or steps itself. Any thoughts on where I went wrong?