Ok, so it's been a while since I've had to integrate(adsbygoogle = window.adsbygoogle || []).push({}); anything, much less something like this.

[tex]\int \frac{1}{n(1 + \ln{n})^{2/3}} dn[/tex]

I'm thinking u substition for ln(n) and then du becomes 1/n? But, since the ln(n) is in the denominator of a fraction raised to a power, wouldn't that mess with du? Or am I on the right track? I checked my calculus book and surfed the web, and couldn't find an integral for ln, so I can't see any other way...

If it helps, this is for a series check by integration to see if it's convergant or divergant, so it goes from nothing to infinity.

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# Homework Help: Integrating with ln in denominator.

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