Integrating (x-5)/√(x-6) with u-Substitution

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SUMMARY

The integral ∫ (x-5)/√(x-6) dx can be solved using u-substitution by letting u = x - 6, which simplifies the expression. The differential du equals dx, and substituting x with u + 6 transforms the integral into ∫ (u + 1)/√u du. This can be further simplified to ∫ (u^(1/2) + u^(-1/2)) du. The integrals of u^(1/2) and u^(-1/2) are straightforward, yielding (2/3)u^(3/2) and 2u^(1/2) respectively, leading to the final solution.

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Homework Statement


Solve with u-substitution
∫ (x-5)/√(x-6) dx

Homework Equations





The Attempt at a Solution


This is what I have done so far and it doesn't seem to work out. I have a feeling I'm missing something. Any help would be appreciated.
u=x-6
du=dx
x=u+6
∫ (u+6-5)(u^(-1/2) du
∫ u^(1/2) + u^(-1/2) du
 
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You were doing just fine until your nerve failed. What's the integral of u^(1/2)du and u^(-1/2)du?
 

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