Can dx/dy always be used for integration and derivation on a circle?

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The discussion clarifies that the relationship dx/dy = x/y is not universally valid, particularly when considering functions like y = x^2, where dy/dx does not equal y/x. It emphasizes the importance of understanding the conditions under which this relationship holds true. The conversation also highlights the distinction between secant and tangent lines, explaining that the secant line's slope represents an average rate of change, while the tangent line's slope reflects an instantaneous rate of change. Counter-examples are provided to illustrate the limitations of applying this formula. Overall, the use of dx/dy = x/y is conditional and requires careful consideration of the specific function involved.
SHOORY
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Homework Statement


is dx/dy= x/y
if yes can i use it always

Homework Equations


for example in a circle
dA/dtheta=A/360

The Attempt at a Solution


if its right sometimes what are the conditions of using it
 
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Generally, no it is not. (You can integrate the expression to find the conditions under which it is true.)
 
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mjc123 said:
Generally, no it is not.
And it is quite easy to find counter-examples. For example, let ##y = x^2##. Then ##dy/dx = 2x \neq y/x = x##.
 
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Orodruin said:
And it is quite easy to find counter-examples. For example, let ##y = x^2##. Then ##dy/dx = 2x \neq y/x = x##.
ok thank you
 
See the graph below for an illustration. The secant is the line through the origin that cuts the curve at (x,y); its slope is y/x. The tangent is the line that touches the curve at (x,y); its slope is dy/dx, the instantaneous slope of the curve at (x,y), or the rate of change of y with x at that point.

tangent & secant.png
 

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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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