Integration Help: Finding x-coord of Point A with y= bx(x -2)

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Discussion Overview

The discussion revolves around solving a mathematical problem involving the curve defined by the equation y = bx(x − 2). Participants are addressing two parts of the problem: finding the value of b given a specific shaded area and determining the x-coordinate of a point A that divides this area into equal parts.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant claims to have found b = -3 after completing part (a) of the problem.
  • Another participant provides a link to a related thread that discusses similar problems, suggesting it may be helpful for the current question.
  • Participants express willingness to assist with further questions as they arise.

Areas of Agreement / Disagreement

There is no explicit disagreement noted, but the discussion remains unresolved regarding the determination of the x-coordinate of point A.

Contextual Notes

The discussion does not clarify the assumptions or methods used to find b, nor does it detail the mathematical steps necessary to find the x-coordinate of point A.

Who May Find This Useful

Students or individuals seeking assistance with integration problems or area calculations in calculus may find this discussion relevant.

kais001
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hey guys,
I am stuck on a question which is
The curve in the picture shown has equation y = bx(x − 2).
(a) Find b given that the shaded area is 4 units 2
(b) Find the x−coordinate of the point A if the line OA divides the shaded area into equal parts.



Ive done part (a) which shows b=-3. From here I am a little stuck. any help would be appreciated
 
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Hello and welcome to MHB, kais001! :D

I would invite you to read the following thread, in which this problem is discussed:

http://mathhelpboards.com/questions-other-sites-52/phyllis-question-yahoo-answers-regarding-finding-line-divides-area-into-equal-parts-7197.html
 
well that handles that quite nicely! I am about to head off for the night but tomorrow ill go over it, if i have any questions do you mind answering them? and thankyou very much for that!
 
kais001 said:
well that handles that quite nicely! I am about to head off for the night but tomorrow ill go over it, if i have any questions do you mind answering them? and thankyou very much for that!

Yes, please feel free to post any questions and I or one of our other helpers will be glad to assist. :)
 

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