MHB Integration Help: Finding x-coord of Point A with y= bx(x -2)

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The discussion centers on solving a mathematical problem involving the curve defined by the equation y = bx(x - 2). The user has successfully determined the value of b as -3 but is struggling to find the x-coordinate of point A that divides the shaded area into equal parts. Other forum members provide encouragement and suggest reviewing a related thread for further assistance. The community expresses willingness to help with any follow-up questions. The focus remains on finding the necessary x-coordinate based on the established value of b.
kais001
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hey guys,
I am stuck on a question which is
The curve in the picture shown has equation y = bx(x − 2).
(a) Find b given that the shaded area is 4 units 2
(b) Find the x−coordinate of the point A if the line OA divides the shaded area into equal parts.



Ive done part (a) which shows b=-3. From here I am a little stuck. any help would be appreciated
 
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Hello and welcome to MHB, kais001! :D

I would invite you to read the following thread, in which this problem is discussed:

http://mathhelpboards.com/questions-other-sites-52/phyllis-question-yahoo-answers-regarding-finding-line-divides-area-into-equal-parts-7197.html
 
well that handles that quite nicely! I am about to head off for the night but tomorrow ill go over it, if i have any questions do you mind answering them? and thankyou very much for that!
 
kais001 said:
well that handles that quite nicely! I am about to head off for the night but tomorrow ill go over it, if i have any questions do you mind answering them? and thankyou very much for that!

Yes, please feel free to post any questions and I or one of our other helpers will be glad to assist. :)
 

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