Integration Help for \int 1/sqrt(a^2 + x^2)

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SUMMARY

The integral \(\int \frac{1}{\sqrt{a^{2} + x^{2}}} dx\) can be solved using the substitution \(x = a \tan(\theta)\). This substitution leads to the result \(\frac{1}{a} \arcsin\left(\frac{x}{a}\right) + C\), where \(C\) is the constant of integration. The discussion highlights the importance of recognizing the integral's relationship to the arcsine function, clarifying that the integral is not directly an arcsine integral without proper substitution.

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Homework Statement




\int \frac{1}{\sqrt{a^{2} + x^{2}}}

Homework Equations


The Attempt at a Solution



I got:\int \frac{1}{\sqrt{a^{2} + x^{2}}} = \sqrt{c} \ast \int \frac{1}{\sqrt{c \ast{x^{2}} + 1}} \frac{1}{a^{2}} = c

NEVERMIND! I got it: I couldn't remember the integral of arcsin..
so it's \frac{1}{a} = cc \ast \int \frac{1}{\sqrt{c \ast{x^{2}} + 1}}<br /> <br /> = c \ast arcsin(cx) /c
 
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holezch said:

Homework Statement




\int \frac{1}{\sqrt{a^{2} + x^{2}}}


Homework Equations





The Attempt at a Solution



I got:


\int \frac{1}{\sqrt{a^{2} + x^{2}}} = \sqrt{c} \ast \int \frac{1}{\sqrt{c \ast{x^{2}} + 1}}


\frac{1}{a^{2}} = c

NEVERMIND! I got it: I couldn't remember the integral of arcsin..
so it's


\frac{1}{a} = c


c \ast \int \frac{1}{\sqrt{c \ast{x^{2}} + 1}}<br /> <br /> = c \ast arcsin(cx) /c


This is not an arcsine integral. :redface:
Try x=a \,\ tan(\theta).
 

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