Integration help, Kepler's problem Lagrangian dynamics

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SUMMARY

The discussion focuses on integrating the expression ψ = ∫[M(dr/r²)] / √(2m(E-U(r)) - (M²/r²) using the substitution u = 1/r for the potential U = -α/r. The user struggles with the integral, which leads to a complex expression. The suggested solution involves completing the square in the denominator's square root and factoring out the coefficient of u², ultimately leading to the answer ψ = arccos((M/r - mα/M) / √(2mE + m²α²/M²)).

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Homework Statement



Carry out the integration ψ = ∫[M(dr/r2)] / √(2m(E-U(r)) - (M2/r2))

E = energy, U = potential, M = angular momentum

using the substitution: u = 1/r for U = -α/r

Homework Equations





The Attempt at a Solution



This is as far as I've gotten: -∫ (Mdu) / √(2m(E + αu) - (M2u2))
I have no idea how to take this integral by hand which seems to be what the question is implying. Wolfram gives me something crazy looking.

My book gives the answer as ψ = arccos( (M/r - mα/M) / √(2mE + m2α2/M2) ) ?




 
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Try "completing the square" of the expression inside the square root in the denominator. Factor out the coefficient of u2 from the square root beforehand.
 
Last edited:

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