Integration Help: Struggling with Distance Qn

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SUMMARY

This discussion focuses on solving integration problems related to distance and work calculations. The first integral, representing distance, is derived as \( s = 10t^2 + \frac{2}{3}t^3 + c \), where \( c \) is determined using given values of \( s \) and \( t \). The second integral calculates work, resulting in \( W = 2e^{2x} + c \), with \( c \) also calculated from provided values. Participants confirmed that both problems require similar integration techniques.

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jwright13
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I’ve always struggled with integration and I don’t know how to do this question, I’m not sure what I’m being asked to calculate. I tried to calculate this as a definite integral but there is no boundary conditions for the distance the object has traveled which is confusing any help would be appreciated thanks! ( it is the bottom question on the pic)
 

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I think you are asking for the first one so integrate the above whole expression and you will get $s= 10t^2 + 2/3 t^3 + c$ now calculate c by putting given values of s and t.
 
DaalChawal said:
I think you are asking for the first one so integrate the above whole expression and you will get $s= 10t^2 + 2/3 t^3 + c$ now calculate c by putting given values of s and t.
Thank you! this helped a lot, do u have any idea with the second question? I struggle with understanding integration any help is great thanks!
 
In the second question, you have to do exactly the same as the first one. Calculate Work it will come out to be $W= 2e^{2x} +c$ now put the values given you will get $W= 2e^{2x} + 6$
 
DaalChawal said:
In the second question, you have to do exactly the same as the first one. Calculate Work it will come out to be $W= 2e^{2x} +c$ now put the values given you will get $W= 2e^{2x} + 6$
Thank you so much! this really helped
 

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