haruspex said:Not sure what your sign convention is for moments. Standard for me is anticlockwise positive. That would make M1 positive and A1x negative. You have the two terms both positive.
I don't understand the presence of the fourth term, q(a-x) etc. You should only include moments coming from one side of the point x.
ok, I understand about the (x-a) terms. I should have noticed the δ(x-a).Engineer_s said:Thanks for your reply. The convention is added beside the drawing. Positive is anticlockwise for me.
M1 is negative but if you cut the beam at let say an distance x from the wall you'll have a moment equal to M1 but in the opposite direction to cancel M1 out and to reach an equilibrium?
q(x-a) is added to cancel out the q*x*x/2 because this last load will continue till the end of the beam but this is not the case. Therefore I had to add the same force in the opposite direction at (x-a) to cancel it out. (this represents the red part on the drawing.)
I hope my explanation is clear. Thanks in advance to help me with my problem.
Best regards
haruspex said:ok, I understand about the (x-a) terms. I should have noticed the δ(x-a).
But you do have a sign error.
I am still confused by your sign convention because you drew the arrow circling clockwise, implying clockwise is positive. You also wrote all of the moments in the M(x) expression as clockwise positive, except the first one. So I am going to assume you are actually taking clockwise positive.
With that comvention, the moment expression is M1+A1x etc., where M1 = -qa2/2 and A1 is qa.
Whatever your convention the those first two terms should have opposite sign.
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