How Can Cylindrical Coordinates Simplify Complex Number Integration?

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SUMMARY

The discussion centers on simplifying complex number integration using cylindrical coordinates. The original integral presented was Σ 1/πn! ∫∫ dx dy exp[-(x^2 + y^2)] (x^2 + y^2)^n I. The user initially struggled with the (x^2 + y^2)^n term while applying Integration by Parts. A suggestion to switch to cylindrical coordinates, transforming the double integral into ∫_0^{2π} dφ ∫_0^∞ r dr, proved successful, leading to a resolution of the problem.

PREREQUISITES
  • Understanding of complex numbers and their representation (e.g., a = x + iy).
  • Familiarity with double integrals and integration techniques, particularly Integration by Parts.
  • Knowledge of cylindrical coordinates and their application in integration.
  • Basic concepts of mathematical analysis and convergence of integrals.
NEXT STEPS
  • Study the application of cylindrical coordinates in multiple integrals.
  • Learn advanced techniques in Integration by Parts for complex functions.
  • Explore the properties of complex integrals and their convergence criteria.
  • Investigate the use of polar coordinates as an alternative to cylindrical coordinates in integration.
USEFUL FOR

Mathematicians, physics students, and anyone involved in complex analysis or integration techniques will benefit from this discussion.

tanaygupta2000
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Homework Statement
Show that (1/π) ∫∫d(Re{a})d(Im{a}) |a><a| = I

where |a> is a coherent state = exp(-a*a/2) (a^n)/√n! |n>
and I is identity operator
Relevant Equations
|a> = exp(-a*a/2) Σ(a^n)/√n! |n>
<a| = exp(-a*a/2) Σ(a*^n)/√n! <n|
|n><n| = I
Capture.PNG


I began this solution by assuming a = x+iy since a is a complex number.
So I wrote expressions of <a| and |a> in which |n><n| = I.
I got the following integral:

Σ 1/πn! ∫∫ dx dy exp[-(x^2 + y^2)] (x^2 + y^2)^n I

I tried solving it using Integration by Parts but got stuck in the (x^2 + y^2)^n part.
Please help how can I evaluate this integral in an easier way.
Thank You !
 
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Why don't you regard x and y are coordinates of xy plane and achieve integration by cylindrical coordinates i.e.
\int dx \int dy = \int_0^{2\pi} d \phi \int_0^\infty r dr
 
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anuttarasammyak said:
Why don't you regard x and y are coordinates of xy plane and achieve integration by cylindrical coordinates i.e.
\int dx \int dy = \int_0^{2\pi} d \phi \int_0^\infty r dr
Yess! It very well worked! Lots of Thanks.
 

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