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[tex]

\int_{0}^\infty e^{-kx}dx=\frac{1}{k}

[/tex]

for real $$k>0.$$

Does this result hold for $$\Re k>0$$ belonging to complex numbers? The reason I have this question is because $$i\times\infty$$ is not $$\infty$$ and so u substitution would not work.

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# Integration of functions of Complex Variables

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