1. The problem statement, all variables and given/known data ∫ (x+2)dx/√(4x-x2) 2. Relevant equations why was the -2 in -2(x-2) was ignored? 3. The attempt at a solution so first i let u= 4x-x2 then, du=4-2x = -2(x-2) so to get (x+2) i equate it to (x-2)+4 so ... ∫ (x+2)dx/√(4x-x2) = ∫(x-2)+4dx/√(4x-x2) = ∫ (x-2)dx/√(4x-x2) + ∫4dx/√(4x-x2) is the solution right? and why was the -2 in -2(x-2) was ignored?