Integration of Rational Functions

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Homework Help Overview

The discussion revolves around evaluating the integral of a rational function, specifically ∫ds/(s^2(s − 1)^2). Participants are exploring the method of partial fractions to decompose the integrand.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to use partial fraction decomposition, equating coefficients to solve for unknowns A, B, C, and D. There are discussions about the correctness of these values and the steps taken to arrive at them.

Discussion Status

Some participants have pointed out potential errors in the original poster's calculations, particularly regarding the value of D. Others are questioning their own approaches and the assumptions made during the coefficient comparison process. There is an ongoing exploration of different interpretations of the problem setup.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There is also a focus on ensuring that the correct application of partial fractions is followed.

forestmine
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Homework Statement



Evaluate the integral. (Remember to use ln |u| where appropriate.)

∫ds/s^2(s − 1)^2


Homework Equations





The Attempt at a Solution



I attempted a solution using the method of partial fractions, but it seems my answer is wrong. Here's what I did...

1=A/s +B/s^2+C/(s-1)+D/(s-1)^2

Then multiplying by a common denominator,

1=As(s-1)^2 +B(s-1)^2 +Cs^2(s-1) + Ds^2
1=A(s^3-2s^2+s) + B(s^2 - 2s +1) + C(s^3 -s^2) +Ds^2

Equating the coefficients and solving for A, B, C, and D, I get A=1, B=1, C=-1, D=3

So my integral now looks like

∫1/s+1/s^2-1/(s-1)+3/(s-1)^2

And taking the integral, I got

lns - 1/s - ln(s-1) + 3/(s-1)

which evidently is wrong.

If anyone can point me in the right direction in terms of where I went wrong, it would be greatly appreciated.

Thanks!
 
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forestmine said:

Homework Statement



Evaluate the integral. (Remember to use ln |u| where appropriate.)

∫ds/(s^2(s − 1)^2)

Homework Equations



The Attempt at a Solution



I attempted a solution using the method of partial fractions, but it seems my answer is wrong. Here's what I did...

1=A/s +B/s^2+C/(s-1)+D/(s-1)^2

Then multiplying by a common denominator,

1=As(s-1)^2 +B(s-1)^2 +Cs^2(s-1) + Ds^2
1=A(s^3-2s^2+s) + B(s^2 - 2s +1) + C(s^3 -s^2) +Ds^2

Equating the coefficients and solving for A, B, C, and D, I get A=1, B=1, C=-1, D=3

So my integral now looks like

∫1/s+1/s^2-1/(s-1)+3/(s-1)^2

And taking the integral, I got

lns - 1/s - ln(s-1) + 3/(s-1)

which evidently is wrong.

If anyone can point me in the right direction in terms of where I went wrong, it would be greatly appreciated.

Thanks!
There is an error in your partial fraction decomposition. D is incorrect.
 
Thanks for the reply!

So for s^2, I got -2A - 2B - C + D = 0

plugging in A, B, and C:

-2(1) - 2(1) - (-1) = 0

and I get D=3?

I'm not seeing where I'm going wrong...
 
Recalculate your parameters and show your work. (I got A=2, B=1, C=-2, D=1. )

ehild
 
Wow, I wonder if I'm going about this all wrong.

Here's what I did:

1=As(s-1)^2 +B(s-1)^2 +Cs^2(s-1) + Ds^2
1=A(s^3-2s^2+s) + B(s^2 - 2s +1) + C(s^3 -s^2) +Ds^2

For x^0 = 1=B

For x = 0 = A + B ----> A=-B=-1 (But that contradicts your answer)

For x^2 = 0 = -2A -2B - C + D

For x^3 = 0 = A + C ----> C=1

Looks like all of my values are wrong. What am I doing incorrectly?
 
forestmine said:
Wow, I wonder if I'm going about this all wrong.

Here's what I did:

1=As(s-1)^2 +B(s-1)^2 +Cs^2(s-1) + Ds^2
Where does the above line come from.

Seems like a strange place to start --- like you're skipping some steps.
 
It comes from here:

1/s^2(s − 1)^2=A/s +B/s^2+C/(s-1)+D/(s-1)^2

And then multiplying all of the above by s^2(s − 1)^2
 
forestmine said:
Wow, I wonder if I'm going about this all wrong.

Here's what I did:

1=As(s-1)^2 +B(s-1)^2 +Cs^2(s-1) + Ds^2
1=A(s^3-2s^2+s) + B(s^2 - 2s +1) + C(s^3 -s^2) +Ds^2

For x^0 = 1=B

For x = 0 = A + B ----> A=-B=-1 (But that contradicts your answer)

For s^1: A-2B=0 A=-2B=-2.


ehild
 
Got it -- I was in fact equating the coefficients incorrectly.

Thanks so much for all the help!
 

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