Integration of V(t) using faraday's law

Click For Summary
SUMMARY

The discussion focuses on integrating the equation derived from Faraday's law for a U-shaped conductor with a sliding bar. The equation to be integrated is dv/(E - BLv) = (LB/mR)dt, where E is the voltage of the battery, B is the magnetic field, L is the length of the rod, and R is the resistance. The user struggles with the integration process, specifically with u-substitution, and seeks assistance in correctly performing the integration to find the velocity as a function of time.

PREREQUISITES
  • Understanding of Faraday's law of electromagnetic induction
  • Knowledge of basic calculus, specifically integration techniques
  • Familiarity with the concepts of electromotive force (EMF) and magnetic fields
  • Experience with physics problems involving motion in magnetic fields
NEXT STEPS
  • Practice integration techniques, particularly u-substitution, in calculus
  • Study the application of Faraday's law in electromagnetic systems
  • Explore the relationship between velocity, magnetic fields, and induced EMF
  • Investigate the dynamics of conductive materials in magnetic fields
USEFUL FOR

Students and professionals in physics, electrical engineering, and anyone involved in the study of electromagnetic induction and motion in magnetic fields.

ilovephysics
Messages
18
Reaction score
0
Ok the question is with a U-shaped conductor and a bar that slides across. There is a battery and a switch, the switch is open for a long time then closed at t=0. I am supposed to find the velocity as a function of time. I am mostly having trouble with the integration, i know the answer but i can't seem to integrate it right.

We have to integrate the first term from 0 to v, and the second from 0 to t

dv/(E-BLv) = (LB/mR)dt

E=voltage of battery
B=magnetic field
L=length of rod
R=resistance

i get to the formula above and then try u-substitution and i can't seem to get it right, could someone integrate this and show me? thanks
 
Physics news on Phys.org
Make the sub

[tex]E-Blv= u[/tex]

You get

[tex]dv=-\frac{du}{Bl}[/tex]

And I'm sure you know how the limits of integration transform...

Daniel.
 

Similar threads

Replies
19
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
8
Views
2K
Replies
5
Views
2K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
1
Views
2K