Integration Problem involving absolute bracket, sine,cosine

[appplejack]

Homework Statement

Evaluate

∫(1)to(-1) l sin(x) l dx

Homework Equations

The Attempt at a Solution

If I just leave it like this, is it wrong?

1. ∫(1)to(-1) l sin(x) l dx = l -cos (x)l

2. l -cos (1) l — l -cos (-1)l = 0 - 0 = 0

 

[Dick]

Way wrong. Split the integral up into regions where sin(x) has a definite sign. Work the integral out on each of those regions. Then add them up. You'll get a very different answer.