# Integration Problem involving absolute bracket, sine,cosine

## Homework Statement

Evaluate

∫(1)to(-1) l sin(x) l dx

## The Attempt at a Solution

If I just leave it like this, is it wrong?

1. ∫(1)to(-1) l sin(x) l dx = l -cos (x)l

2. l -cos (1) l — l -cos (-1)l = 0 - 0 = 0