Integration-Problem with substitution

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SUMMARY

The integration problem discussed involves the integral t = (2pa/mv^2) * ∫[r*dr]/[((b^2 + r^2)^(3/2))(sqrt(r^2 - p^2))], which arises from mechanics related to small angle scattering. The user attempted substitutions such as y = r^2 and y = b^2 + r^2 but found them ineffective. A suggestion was made to use the substitution u = r^2 - p^2, although its efficacy is uncertain. The recommended approach is to apply a trigonometric substitution, specifically sec(θ) = r/p, to simplify the integral.

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Homework Statement


I have reached this integration from a mechanics problem about small angle scattering. t= (2pa/mv^2)*(int from p to infinity) [r*dr]/[((b^2 +r^2)^(3/2))(sqrt(r^2 - p^2))]


Homework Equations





The Attempt at a Solution


I know that there should be a substitution that will make this an easy problem, but I can't find it. I've tried the simple ones like let y=r^2, or y=b^2 + r^2, but they didn't get me anywhere.
 
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For further reference, here is your integral in a more readable form:
[tex]\frac{2pa}{mv^2}\int_{r = p}^{\infty}\frac{r~dr}{(b^2 + r^2)^{3/2}\sqrt{r^2 - p^2}}[/tex]

You might try an ordinary substitution of u = r2 - p2, but I'm not sure that will do you much good. Next I would try a trig substitution, sec [itex]\theta[/itex] = r/p.
 

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