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Integration-Problem with substitution

  • Thread starter jameson2
  • Start date
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1. Homework Statement
I have reached this integration from a mechanics problem about small angle scattering. t= (2pa/mv^2)*(int from p to infinity) [r*dr]/[((b^2 +r^2)^(3/2))(sqrt(r^2 - p^2))]


2. Homework Equations



3. The Attempt at a Solution
I know that there should be a substitution that will make this an easy problem, but I can't find it. I've tried the simple ones like let y=r^2, or y=b^2 + r^2, but they didn't get me anywhere.
 
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For further reference, here is your integral in a more readable form:
[tex]\frac{2pa}{mv^2}\int_{r = p}^{\infty}\frac{r~dr}{(b^2 + r^2)^{3/2}\sqrt{r^2 - p^2}}[/tex]

You might try an ordinary substitution of u = r2 - p2, but I'm not sure that will do you much good. Next I would try a trig substitution, sec [itex]\theta[/itex] = r/p.
 

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