Integration Proof: Proving/Refuting |f(x)-g(x)| Integrable on [a,b]

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SUMMARY

The discussion centers on proving whether the function |f(x) - g(x)| is integrable on the interval [a, b] given that f(x) and g(x) are integrable functions on the same interval. The triangle inequality |f(x) - g(x)| ≤ |f(x)| + |g(x)| is utilized to establish the finiteness of the integral. Additionally, the approximation of f and g using step functions is suggested as a method to demonstrate the integrability of their difference.

PREREQUISITES
  • Understanding of integrable functions on closed intervals
  • Familiarity with the triangle inequality in real analysis
  • Knowledge of step functions and their properties
  • Basic concepts of limits and convergence in calculus
NEXT STEPS
  • Study the properties of integrable functions on closed intervals
  • Learn about the triangle inequality and its applications in analysis
  • Explore the concept of step functions and their role in approximating integrals
  • Investigate the relationship between the integrability of functions and their differences
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Students and educators in calculus, particularly those studying real analysis and integration theory, as well as mathematicians interested in the properties of integrable functions.

Rony
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Homework Statement



prove or refute : let f(x), g(x) be integrable functions on [a,b] so |f(x)-g(x)| integrable on a [a,b]

Homework Equations





The Attempt at a Solution


I'm pretty sure that it's right, I just can't find formal proof, someone can give me direction.
 
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Welcome Rony,
Use the triangle inequality |f(x)-g(x)| <= |f|+|g| to prove finiteness & the fact that f-g can be approximated with the corresponding differences of step functions
approximating f & g.
 

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