Integration Question I have a midterm in 45 mins AH

Click For Summary

Homework Help Overview

The discussion revolves around an integration problem involving the Fundamental Theorem of Calculus (FTC) and the determination of a function f(t) from a definite integral with variable bounds. The original poster expresses urgency due to an impending midterm.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various methods such as substitution and partial fractions. The original poster indicates uncertainty about the required method and expresses difficulty in recalling relevant techniques. Others suggest differentiating the integral expression to find f(t) and using the chain rule due to the variable upper limit.

Discussion Status

The discussion is active, with participants providing insights on how to approach the problem. Some guidance has been offered regarding the application of the FTC and differentiation, but there is no explicit consensus on the method to be used.

Contextual Notes

The original poster is under time pressure due to an upcoming midterm, which may influence the depth of exploration in the discussion.

deerhake.11
Messages
7
Reaction score
0
Integration Question.. I have a midterm in 45 mins! AH!

Homework Statement



integral with bounds [5,x^2] of f(t)dt = (5x^2)/(x^4+6) + C

f(t) = ?
C = ?

Homework Equations



Uhm.. I don't know. I am guessing you have to use the FTC.

The Attempt at a Solution



I've have tried so many different types of substitution and stuff with no luck. I really have no idea what method is required to solve this; I don't remember learning it.
 
Physics news on Phys.org
Probably way beyond me but have you tried partial fractions? And substitution?

Can you show what you've tried?
 
Last edited:
The FTC says that

[tex]\int_a^b f(t)dt = F(b)-F(a)[/tex]

where F'(t)=f(t).

So you want to find which function F(t) is such that F(x²) = -(5x^2)/(x^4+6). Then differentiate it to get f(t). About C, well C=F(5), so once you get F(t), finding C is a formality.
 
Yes, the derivative of [tex]\int_a^x f(t)dt[/itex] is f(x). But you are given [itex]\int_a^{x^2} f(t)dt[/itex]. Let u= x<sup>2</sup> and use the chain rule: [itex]\frac{df}{dx}= \frac{df}{du}\frac{du}{dx}[/itex].<br /> <br /> To determine C, let x= some convenient value and evaluate.[/tex]
 

Similar threads

Replies
2
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
1K
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K