You can as long as the series converges between the limits of integration.
[tex]
\begin{align*}<br />
\int \frac{\tan x}{x} dx &=\int \frac{1}{x}\sum_{n=1}^\infty \frac{B_{2n} (-4)^n(1-4^n)}{(2n)!} x^{2n-1} dx \\<br />
&=\sum_{n=1}^\infty \left( \frac{B_{2n} (-4)^n(1-4^n)}{(2n)!} \int x^{2n-2} dx \right)<br />
\\<br />
&=\sum_{n=1}^\infty \frac{B_{2n} (-4)^n(1-4^n)}{(2n)!(2n-1)} x^{2n-1} <br />
\\<br />
&=x+\frac{x^3}{9}+\frac{2x^5}{75}+...\;\;\; \text{for} \;|x|<\frac{\pi}{2}<br />
\end{align}[/tex]
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