given,-(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\vec{a}[/tex][tex]_{x}[/tex]=6t[tex]^{2}[/tex]

[tex]\vec{a}[/tex][tex]_{y}[/tex]=-4

vector V(t=0)=0

Vector R(t=0)=0

1-the displacement from the 1st to the 3rd second

2-the distance travelled fron the 2st to 3rd second

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using integration,

Vx=[tex]\int[/tex](ax)dt=2t[tex]^{3}[/tex]

Vy=[tex]\int[/tex](ay)dt=-4t

x=[tex]\int[/tex](Vx)dt=0.5t[tex]^{4}[/tex]

y=[tex]\int[/tex](Vy)dt=-2t[tex]^{2}[/tex]

then i found r(t=1)=(0.5,-4)

and r(t=3)=(40.5,-18)

delta(r)=42.38, which is the answer to question 1

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now to find the distance travelled what i would like to do is integrate the vector V from 1 to 3, but once i get an answer for x and y, how do i connect them to get the scalar D, the distance he travelled?

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# Homework Help: Integration, where am i going wrong here?

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