senorarosada Messages 1 Reaction score 0 Thread starter Mar 29, 2012 #1 I wonder how would I get out the integral when the denominator is square-rooted. ∫[itex]\frac{1}{\sqrt{3x-x^2}}[/itex] dx
I wonder how would I get out the integral when the denominator is square-rooted. ∫[itex]\frac{1}{\sqrt{3x-x^2}}[/itex] dx
dodo Messages 695 Reaction score 2 Mar 29, 2012 #2 Hi, http://www.sosmath.com/calculus/integration/trigsub/trigsub.html Be sure to read till the end, where it speaks of "completing the square".
Hi, http://www.sosmath.com/calculus/integration/trigsub/trigsub.html Be sure to read till the end, where it speaks of "completing the square".
JJacquelin Messages 801 Reaction score 35 Mar 29, 2012 #3 3x-x² = (3/2)²-(x -(3/2) )² Let (x -(3/2) )= (3/2)*sin(t) or let (x -(3/2) )= (3/2)*sinh(t)