Integration within a DiffEQ problem

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SUMMARY

The discussion focuses on solving the differential equation (x² + xy + 3y²)dx - (x² + 2xy)dy = 0 using the substitution y = ux and dy = udx + xdu. The user successfully transformed the equation to the form dx/x = (2u + 1)/(u² + 1)du but encountered difficulties integrating the right-hand side. Another participant suggested splitting the integral into two parts: 2u/(u² + 1) and 1/(u² + 1), recommending substitution for the first part and recognizing the second part as an arctangent integral.

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Homework Statement


Solve the given differential equation by using an appropriate substitution.



Homework Equations


[tex](x^{2}+xy+3y^{2})dx-(x^{2}+2xy)dy=0[/tex]
[tex]y=ux, dy=udx+xdu[/tex]


The Attempt at a Solution


[tex](x^{2}dx+ux^{2}dx+3u^{2}x^{2}dx)-(ux^{2}dx+x^{3}du+2u^{2}x^{2}dx+2ux^{3}du)=0[/tex]
After combining, cancelling and moving terms into their appropriate places, I get:
[tex]\frac{dx}{x}=\frac{2u+1}{u^{2}+1}du[/tex]


This is where I get stuck, I am unable to integrate the right hand side. Can anyone help me out a little?

Thanks.
 
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Split it into two parts. 2u/(u^2+1) looks easy by a substitution and 1/(u^2+1) looks like an arctan.
 
I cannot believe I didn't see that.

Thanks!
 

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