Intensity of light through two polarizers

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SUMMARY

The intensity of unpolarized light of 3 W/m² passing through two polarizing films with axes 60 degrees apart can be calculated using the equation I₂ = I₁ * cos²(φ). Initially, the intensity after the first polarizer is halved, resulting in I₁ = 1.5 W/m². Subsequently, applying the angle of 60 degrees in the equation yields an intensity of I₂ = 1.5 W/m² * cos²(60°), resulting in an output intensity of 0.375 W/m² after the second polarizer.

PREREQUISITES
  • Understanding of unpolarized light and its properties
  • Familiarity with the concept of polarization
  • Knowledge of trigonometric functions, specifically cosine
  • Proficiency in applying the intensity transmission equations for polarizers
NEXT STEPS
  • Study the derivation of the intensity transmission formula for polarizers
  • Learn about the behavior of light through multiple polarizers
  • Explore the concept of Brewster's angle and its applications
  • Investigate the effects of varying angles between polarizers on light intensity
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the principles of light polarization and intensity transmission through polarizing filters.

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Homework Statement



Unpolarized light of intensitry 3 W/m^2 goes through two polarizing films. Their axes are 60 degrees apart. What is the intensity of light transimitted by the second film

Homework Equations


##I_2 = I_1*cos^2 phi##
Where I_1 is the intensity of light after going through the first film and I_2 is the intensity of light after going through the second film.

I also read online that the intensity of light going through one polarized lens is one half the original intensity, I don't know if I should use that since we never learned it in class and its not in the lab manual

The Attempt at a Solution


I don't know whether to just use the first equation and plug the 3W/m^2 in for I_1, or to use both equations(use half of 3 W/m^2 as I_1), which I don't think their expect since I was only given the first equation.
 
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The problem clearly states that you start with unpolarized light. Why could you then assume that it all goes through the first polarizer?
Mddrill said:
I also read online that the intensity of light going through one polarized lens is one half the original intensity, I don't know if I should use that since we never learned it in class and its not in the lab manual
Can't you figure that factor out with the equation you are given?
 
The equation I was given was I_2=I_1cos^phi. How would I figure ou the second equation from that?

I just want to make sure I'm not missing something because I feel like I should be able to solve the problem with just the equation I'm given.
 
Mddrill said:
The equation I was given was I_2=I_1cos^phi. How would I figure ou the second equation from that?
For unpolarized light, you can consider that all polarizations are equiprobable. So you can calculate, on average, how much of that light will pass through the first polarizer using that equation.
 

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