Intensity of sound wave and energy

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A sound wave with an intensity of 2x10^(-3) W/m^2 is considered modestly loud, and the energy transferred to a 6.0 mm diameter eardrum over one minute was calculated. The power was determined using the formula P=IA, resulting in 2.2610x10^-7 W. However, the final energy calculation of 1.3572x10^-5 J was questioned for accuracy. A suggestion was made to recheck the area calculation to ensure the correct answer. Accurate calculations are crucial for understanding sound wave energy transfer.
Pambos
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Homework Statement



A sound wave with intensity 2x10^(-3) W/m^2 is perceived to be modestly loud. Your eardrum is 6.0 mm in diameter. How much energy will be transferred to your eardrum while listening to this sound for 1.0 min?

Homework Equations


P=IA=(intensity)(area)
=2x10^(-3) * (pi (6x10^-3)^2)
=2.2610x10^-7 W

The Attempt at a Solution


P=IA=(intensity)(area)
=2x10^(-3) * (pi (6x10^-3)^2)
=2.2610x10^-7 W

P=delta E/ delta t
=2.2610x10^-7 J/s * 60 s
=1.3572x10^-5 J

..its not the correct answer can anyone help?
 
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Hi Pambos, Welcome to Physics Forums!

Check your area calculation.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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