Interest continuously compounding with a variable prinicple

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SUMMARY

The discussion centers on calculating the time required for continuously compounded interest on a variable principal of $1 to equal the principal itself, specifically using the formula F=Pert. The user derived that at a 15% interest rate, the time required is approximately 3.96 years, while at an 8% interest rate, it is about 7.27 years. The user also confirmed that previous estimates of 13.8 years, 20 years, and 7.5 years were incorrect. The analysis emphasizes the importance of accurately setting up the problem and correctly applying the continuous compounding formula.

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venik
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Homework Statement


This is a question I *might* have already got the answer to, I'd just like for someone very good with calculus and algebra to verify/answer the question themselves.

To be more exact with the problem, we are putting 1 dollar (a variable principle) into a continuously compounded interest account at rate r. At what moment does one year's interest (e^r-1), equal our principle of 1 dollar per year. Or at what time can we stop putting the dollar in completely.

I solved it as the most complicated substitution problem I, personally, have ever done. Feel free to do it any way you please, but I'm looking for both answers and/or possible mistakes in my math.

Homework Equations


F=Pe^rt

The Attempt at a Solution



Let F = Final, P = principle, r = interest rate, y = years.
Given that:
F = Pe^(ry)

And

P1 = ($)1 x y
(P1 because I'm going to have to use another P later)

Then replacing 1y for P we get

F = ye^(ry)

This gives us F for any time y, and rate r.

But we want a specific F, to get that I first defined what P2 is required for the next year's interest to be equal to the 1 dollar we are putting in every year.

P2(e^r-1) = 1

P2=1/(e^r-1)

In order to substitute this into our original equation we must substitute P2 into a separate F = Pe^(rt2)

We know that t2 = 1 because in the question we asked when does (e^r-1) of the *last* year equal $1.

We get

F = e^r/(e^r-1)

Then substitute this final into our F = ye^ry

we get

e^r/(e^r-1) = ye^ry

0 = ye^ry - e^r/(e^r-1)

at 15% interest I get y = 3.96 years. Graphing on my calculator because as far as I know that is unsolvable algebraically

at 8% interest I get y = 7.27 years.

Sounds too good to be true. Put $20k in a savings account for 4-7 years and you will raise your wage $20k/year for the rest of your life? Start investing! It will be free soon. lol.

This is only my most recent approach to this problem. Other answers which I have debunked are (for 8% interest) 13.8 years, 20 years, and 7.5 years. I'd like confirmation, or a correct answer please.
 
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I think you haven't gotten any responses because it's not at all clear exactly what the set-up of the problem is.
 

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