Interesting angle of elevation problem

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Homework Help Overview

The discussion revolves around a projectile motion problem involving the angle of elevation and its relationship to maximum height and horizontal range. The context includes gravitational acceleration on Earth.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to relate the maximum height of a projectile to its horizontal range through equations but expresses uncertainty in rearranging them. Some participants question the correctness of the range equation provided, while others offer a corrected version. Additionally, a new problem regarding gravitational effects at different elevations is introduced, prompting further inquiry.

Discussion Status

The discussion is active, with participants providing feedback on the equations used and suggesting corrections. There is a shift in focus as the original poster seeks help with a different problem, indicating a branching of topics. No consensus has been reached on the initial problem, but guidance has been offered regarding the range equation.

Contextual Notes

Participants are navigating through the complexities of projectile motion equations and their applications, with some expressing confusion over the setup and calculations. The introduction of a new problem suggests a need for clarity on gravitational concepts at varying elevations.

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Homework Statement


What is the angle of elevation of a projectile that travels THREE time horizontally its MAXIMUM height, on earth

g = 9.800m/s2

Homework Equations



Equation 1 - H = ((vsinθ)2)/2g

Equation 2 - R = 2v2((sinθcosθ)2/g

The Attempt at a Solution



I tried making 3x(equation 1)=equation 2, and letting v=5m/s, and then solving for θ, but I don't think I rearranged the equation properly. THE ANSWER IS FOR SURE 53.13°, I JUST HAVE TO SHOW HOW TO GET IT
Thanks for any help
 
Last edited:
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Equation for range is not right.
 
lewando said:
Equation for range is not right.

What is the equation for range? And could you help me with it?
 
R = 2v2sinθcosθ/g. That should get you going.
 
i still can't figure it out
 
Nothing wrong with your original approach (3H = R). Show your work so you can more specifically show where you are having a problem.
 
I don't need help with that one anymore, but if you could help me with a different problem, it would be great.

a)To what elevation must one go to decrease your "weight" to one sixteenth (1/16) of its "surface" value?

b) At the elevation calculated in part a), what is the period of this orbit?

G = 6.670x10^-11
R(earth) = 6.380x10^6
M(earth) = 5.98x10^24
 
You should start a new thread, following the template, listing all relevant equations, showing your work, etc.
 
thats all i have, i have no idea how to solve it
 

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