You have a device that shoots an object at an angle, on top of a desk.
You have x,y and v solve for the angle.
Origin is at the top of the desk.
x = vxot
vsinΘ = vyo
vcosΘ = vxo
The Attempt at a Solution
y= vsinΘt + (1/2)at^2
x = vcosΘt → t = x/(vcosΘ)
y = x*(vsinΘ)/(vcosΘ) +(1/2)a(x/(vcosΘ))^2
y = xtanΘ + (a/2)*((x^2)/(v^2cos^2Θ))
from here i moved cos^2Θ to the left and changed tanΘ into sincos but I don't know how to isolate the Θ by itsself.
Does anyone have any ideas? I know quadratic equation can be used but i don't know how to change it for Θ
Any help is appreciated.[/B]