How Do Magnetic Planes Influence Current Density in Conductive Materials?

Click For Summary

Homework Help Overview

The discussion centers around the behavior of electromagnetic waves interacting with a magnetic, conducting material. The original poster describes a scenario involving an infinite plane of such material and explores the generation of current density due to incoming waves.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to analyze the wave interactions at the material interface, considering reflections and transmissions. They question the implications of differing frequencies on the wave behavior within the material. Other participants raise concerns about the propagation of electromagnetic waves in conductive materials and the behavior of the electric field inside the material.

Discussion Status

Participants are actively exploring the implications of wave behavior in conductive materials, with some guidance offered regarding the conditions under which waves may enter the material. There is an acknowledgment of differing perspectives on the electric field's behavior within the material.

Contextual Notes

There is a mention of the material's conductivity being frequency-dependent, which may influence the wave propagation and current density generation. The original problem's constraints and assumptions are under examination, particularly regarding the nature of the waves and the material properties.

carllacan
Messages
272
Reaction score
3

Homework Statement


We have an infinite plane of width 2b made of a magnetic, conducting material (μr >> 1, σ >> 1). Two monochromatic electromagnetic plane waves, with magnetic excitation vector amplitude Hs approach it, each one traveling towards one of its two faces. Find the current density J generated.

Homework Equations

The Attempt at a Solution


I've taken the plane to be parallel to the XZ plane and centered on it, that is, it extends from y = -b to y = +b, for every z and x. The waves are traveling from y = -∞ and from y = ∞, respectively. I assumed that the frequencies and phases of both waves are equal.

Physically, here's what I think would happen: each wave will divide in a reflected and a transmitted wave upon reaching the interface. This transmitted wave will travel inside the material until it reaches the opposite interface, where it will again divide into a transmitted wave (into the air) and a reflected wave (into the material). This last reflected wave will repeat the process, infinitely.

Mathematically, what I've done so far is to set the equations for all the waves (only their H vector, since is what I'm given). For each region (y < -b; -b < y < b and y > b) I have a sum of two waves in opposite directions. I think it would suffice to use the boundary conditions for the H vector and find the six waves. The amplitudes of these waves will account for the "infinite" transmitted and reflected waves. Am I right?

Once I have the waves insides the material ##\vec J ## can be found just using ## \vec ∇ × \vec H = \vec J ##

Now, what if the frequencies were different? I think I would set, (a) on y < b, three waves, an incident wave from y = -∞ with frequency ω and two waves traveling from y = -b to y = -∞ with freqs ω and ω' (b) on -< < y < b four waves, one for each combination of directions and frequency, and (c) on y > b three waves similar to on y < -b, and then use the B. C. as before.
 
Physics news on Phys.org
How can an EM wave enter a conductive material? Would not the E-field be reduced to zero, and the wave not propagate?
 
Now that you mention it I have completely overlooked that detail. The exercise is redacted exactly as in my post, so... the field inside will just be 0?
 
Ok, the material is not a conductor to all frequencies, so if the waves have an appropriate ω they will enter the material.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
2K
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
7K