1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Intermediate Value Theorem Excercise

  1. Sep 24, 2009 #1
    If f(x) = x^2 + 10sinx, show that there is a number c such that f(c) = 1000




    Well since I was not given an interval to find a root on, I decided to set the equation equal to 1000 and solve it.

    My work:
    f(x)=x^2 + 10sinx=1000
    x^2 = 1000-10sinx
    x= +/- (1000 - sinx)^1/2
     
  2. jcsd
  3. Sep 24, 2009 #2

    nicksauce

    User Avatar
    Science Advisor
    Homework Helper

    That is a transcendental equation... you're not going to be able to find an analytic solution. My suggestion: Since 10sin(x) is bounded between -10 and +10, you know that the answer will be in the interval √990 and √1010. Now apply the intermediate value theorem to that interval.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Intermediate Value Theorem Excercise
Loading...