Internal energy does or does not depend on volume of molecules?

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SUMMARY

The internal energy of an ideal gas is independent of the volume occupied by the gas molecules, as established in thermodynamic principles. This independence is particularly evident during adiabatic changes, where internal energy changes are determined solely by temperature variations, represented by the equation ΔU = Cv (Tf - Ti). In expansion work scenarios, while work is done (w = Pex x ΔV for irreversible expansion or w = -nRTln(Vf/Vi) for isothermal reversible expansion), the internal energy remains unchanged if the heat supplied equals the work done, resulting in ΔU = 0.

PREREQUISITES
  • Understanding of ideal gas laws
  • Familiarity with thermodynamic concepts such as internal energy and adiabatic processes
  • Knowledge of work and heat transfer in thermodynamic systems
  • Basic grasp of equations related to internal energy changes (ΔU = Cv (Tf - Ti))
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  • Study the principles of adiabatic processes in thermodynamics
  • Learn about the derivation and application of the first law of thermodynamics
  • Explore the concept of isothermal processes and their impact on internal energy
  • Investigate the relationship between work done and internal energy in various thermodynamic cycles
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p3t3r1
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I am kind of confused by the conflict of the following two concepts.

If I understood correctly, internal energy of a system is independent of the volume occupied by the gas molecules. This is because the gas molecules are assumed to be ideal and therefore have no intermolecular interactions. (Hence volume doesn't matter)

This is proven to be true in adibatic change, where both volume and temperature changes.

If I understood correctly, this adibatic change can be divided into volume change at constant temperature, and temperature change at constant volume.

However, for the change in the internal energy, only the second step matters and hence delta U = Cv (Tf-Ti)

I fail to see how this applies in expansion work. In expansion work, delta U = w + q.

w = Pex x delta V for irreversible expansion

and

w = -nRTln(Vf/Vi) for isothermal reversible expansion.


Well if work is done, then the internal energy must change. So wouldn't this mean that the internal energy is dependent on the volume of the molecules?

(Unless of course the heat supplied by the surroundings is equal to the work done by the system to keep the process isotherma; and these two cancel each other out to give delta U = 0?)

Thanks!
 
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