Enthalpy Explained: All You Need to Know

AI Thread Summary
Enthalpy is a thermodynamic property that combines internal energy with the work done to expand a system against external pressure, making it particularly useful for processes occurring at constant pressure. Unlike internal energy, which only accounts for energy changes within a system, enthalpy also considers the energy required for volume changes, making it essential for analyzing exothermic and endothermic reactions. The discussion highlights that while internal energy is sufficient for constant volume processes, enthalpy simplifies calculations in constant pressure scenarios, which are common in chemical reactions and engineering applications. The distinction between these two properties is crucial for understanding energy transfers in thermodynamic systems. Overall, enthalpy provides a more comprehensive view of energy changes when external work is involved.
  • #51
Sailor Al said:
I can find no "rules" for its use. No-one is saying there is a law of conservation of enthalpy.
I am a layman in aerodynamics. However, this is my view on your concern. In thermodynamics, $$dH=TdS+VdP$$ So, in an adiabatic, isobaric reversible process, ##dS=0, dP=0## the enthalpy##(H)## remains conserved.

Air is normally considered as insulator of heat. So if you consider a chunk of air as your system, all the thermodynamical changes within it are assumed to occur in the adiabatic way. In atmospheric science, adiabatic lapse rate is an example of such assumption which works well.

In addition, if some aerodynamical study is meant to pursue in a constant pressure zone, say, at a narrow range of altitude, then the study eventually becomes adiabatic, isobaric where H is constant as mentioned above. That may be the reason to introduce enthalpy.

Having said so, I don't know and couldn't realise either what kind of thermodynamical changes we see for a parcel of air, if the process is simultaneously adiabatic and isobaric. For an ideal gas, adiabaticity implies ##PV^{\gamma}=##constant. If we further set ##P## constant for isobaric process, then ##V## must become constant. Hence, no work done, no heat exchange and ##dU=0##. So everything stand still.

For a non-ideal gas, some meaningful changes may occur.
 
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