Intersecting x_1x_2 Plane and Curve x at t=π/2

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The discussion focuses on finding the intersection of the x_1x_2 plane and the normal plane to the curve defined by the equation x = (cos(t)e_1 + sin(t)e_2 + te_3) at t = π/2. The tangent vector at this point is determined to be -e_1 + e_3, leading to the normal plane equation -x_1 + x_3 - π/2 = 0. The x_1x_2 plane is defined by x_3 = 0, and the intersection of these two planes results in a line described by the equations x_3 - x_1 = π/2 and x_3 = 0.

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Homework Statement


Find the intersection of the x_1x_2 plane and the normal plane to the curve
x= (cos(t)e_1 + (sin(t))e_2 + (t)e_3

At the point t = pi/2


Homework Equations




I have looked everywhere for a formula or an example for this and cannot find one? Can anyone help me as to what I should be looking up, if there is a formula, or a hint on the method I should try.

Thanks
 
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First, determine the planes! The tangent vector to cos(t)e_1 + (sin(t))e_2 + (t)e_3
is -sin(t)e_1+ cos(t)e_2+ e_3 and at pi/2 that is -e_1+ e_3. Of course, at pi/2, the curve goes through the point e_2+(pi/2)e_3.

The equation of a plane with normal vector -e_1+ e_3 containing point (0,1,pi/2) is, of course, -x_1+ x_3- pi/2= 0 or x_3- x_1= pi/2.

I assume you know that the equation of the x_1x_2plane is x_3= 0.

Find all points that satisfy x_3- x_1= pi/2 and x_3= 0. The intersection of two planes is, of course, a line.
 
Why did you look for the formula? Such things are easy to derive for yourself.
 

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