Intersection between a plane and a line

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SUMMARY

The discussion focuses on calculating the intersection point between a plane defined by the equation ax + by + cz + d = 0 and a straight line represented as X = X0 + vt. To find the intersection, one must derive the value of "t" that satisfies the plane equation for the parametric equations of the line. Additionally, determining whether two points are on the same side or different sides of the plane involves evaluating the plane equation for each point and comparing the results.

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  • Familiarity with parametric equations of lines
  • Knowledge of plane equations in three-dimensional space
  • Basic algebraic manipulation skills
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Asuralm
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Hi all:
Given a plane ax+by+cz+d = 0, and a straight line, X = X0 + vt. What is an efficient way to compute the intersection point please? Also, is there any efficient method to determine if two points are located on the same side of the plane or on the different side of the plane?

Thanks for your help
 
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I've moved your thread to the Homework Help section of the site.

As per the guidelines of Physics Forums, we would like to see your attempt at the problem before helping you with it.

Thanks,

Tom
 
How to derive the answer should be obvious to you if you use a good enough notation!

Remember that for any t in R, there corresponds a point (x,y,z) on the line given by the equations:
x=x_{0}+v_{x,0}t, y=y_{0}+v_{y,0}t, z=z_{0}+v_{z,0}t

Furthermore, what requirement exists so that a point (x,y,z) is guaranteed to lie on the PLANE?

In particular, what equation for "t" do you get out of this?
(Remember that once you have found the required t-value, computing the specific values of the coordinates of the point is trivial)
 
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