Intersections of a Line and a Parabola: Solving for t

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SUMMARY

The discussion focuses on solving for the intersection points of the line L(t) = <1+5t, 3+t> with the parabola y = x^2. The line intersects the x-axis at (-14, 0) when t = -3 and the y-axis at (0, 14/5) when t = -1/5. The user initially struggled with setting up the equation (3+t) = (1+5t)^2 to find the intersection with the parabola but ultimately resolved the issue through basic algebra. The correct values of t for the intersections with the parabola were not explicitly provided in the discussion.

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Homework Statement


Consider the line L(t)=<1+5t, 3+t>. Then L intersects:
1. The x-axis at the point (-14,0) when t= -3
2. the y-axis at the point (0, 14/5) when t=(-1/5)
3. the parabola y=x^2 at the points ____ and ____ when t=____ and ____.


Homework Equations



y=x^2?

The Attempt at a Solution



I really have no idea what this is asking. I tried setting y = x^2 so (3+t) = (1+5t)^2 with the results of (110/50) and (272/50) but it didn't work. I really have no idea what it's asking. I'm sure it's a very simple problem because this is number 2/16 on my homework and I've already gotten all the others correct (including #1 and #2 of this problem), I just need a little push in the right direction.
Thanks!
 
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I think you are doing the right thing. But you are getting the wrong solutions for t. Unfortunately, when I work it out I get a pretty messy solution for the two values of t. Can you show how you solved it?
 
NEVER MINE I figured it out... basic algebra problem it works now!
 
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