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Introductory analysis question
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[QUOTE="Office_Shredder, post: 4539032, member: 53426"] Part 1 is not good, as all you've shown is that -1 would be in the set if negative numbers were allowed in the set (which they aren't anyway). Part 2 and 3 are basically OK but you have some language issues (which also show up in part 1). When you say you haven't said anything meaningful. [itex] H^2 \geq 3 [/itex] isn't an upper bound, it's a condition which upper bounds must satisfy. A correct statement would be something like 'therefore if H is an upper bound, [itex] H^2 \geq 3[/itex]. For part b you basically want to copy your (2) idea. You know that if H is an upper bound of S in Q then H is not equal to [itex] \sqrt{3}[/itex] - or you should go ahead and prove that the square root of 3 is irrational - so H[sup]2[/sup] > 3 strictly. Therefore (H-1/N)[sup]2[/sup] > 3 if N is small enough (you have to prove this). [/QUOTE]
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Introductory analysis question
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