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Introductory Simple Harmonic Motion Problem

  1. Jun 2, 2014 #1
    Q: When a sound wave with a certain intensity is detected by the tympanic membrane, the amplitude of the resultant motion is 1.0 nm (1.0 x 10-9 m). If the frequency of the sound is 600 Hz, what is the maximum speed of the membrane oscillation?

    My answer:

    1)Vmax = wA (where w= angular velocity)
    2)w = 2(pi) x f = 2(pi) x 600 Hz
    3) ^Then I insert the above result of 'w' into the first equation

    Is this correct? Additionally, is there a simpler way to do this?

    Any replies will be very much appreciated :)
     
  2. jcsd
  3. Jun 2, 2014 #2

    Simon Bridge

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    That's pretty much it yep - multiplying a bunch of numbers together is as simple as it gets.

    It is best practice to do the algebra before you plug in the numbers though ... so for oscillations of amplitude A and frequency f, the max speed for the membrane is ##v = \omega A = 2\pi f A##.
     
  4. Jun 2, 2014 #3
    That seems simple enough, I'd think.
     
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