- #1
Luke Tan
- 29
- 2
- TL;DR Summary
- When it is mentioned that the poisson bracket is invariant under a canonical transformation, does this mean the functional form of the poisson bracket, or the numerical value?
I've recently been starting to get really confused with the meaning of equality in multivariable calculus in general.
When we say that the poisson bracket is invariant under a canonical transformation ##q, p \rightarrow Q,P##, what does it actually mean?
If the poisson bracket ##[u,v]_{q,p}## were, say, ##[u,v]_{q,p}=q-p##, does the invariance mean that the poisson bracket is ##[u,v]_{Q,P}=Q-P##?
This would seem to make the least sense to me.
However, the only other definition I can think of would be that the numerical value is conserved, say if we had ##P=-q##, ##Q=p##, the poisson bracket ##[u,v]_{Q,P}=-P-Q##, and this would make sense for the most part to me.
However, this would then raise the confusing question as to what the significance of this invariance is. From what I can see, any transformation equations ##Q=Q(q,p)## and ##P=P(q,p)## can easily be inverted to get ##q=q(Q,P)## and ##p=p(Q,P)##, which we then substitute into the poisson bracket, or any other function as a matter of fact, and this will naturally satisfy the condition that the numerical value is invariant.
Which is the correct definition of invariance, and if it's that the numerical value doesn't change, why then is this invariance so significant?
When we say that the poisson bracket is invariant under a canonical transformation ##q, p \rightarrow Q,P##, what does it actually mean?
If the poisson bracket ##[u,v]_{q,p}## were, say, ##[u,v]_{q,p}=q-p##, does the invariance mean that the poisson bracket is ##[u,v]_{Q,P}=Q-P##?
This would seem to make the least sense to me.
However, the only other definition I can think of would be that the numerical value is conserved, say if we had ##P=-q##, ##Q=p##, the poisson bracket ##[u,v]_{Q,P}=-P-Q##, and this would make sense for the most part to me.
However, this would then raise the confusing question as to what the significance of this invariance is. From what I can see, any transformation equations ##Q=Q(q,p)## and ##P=P(q,p)## can easily be inverted to get ##q=q(Q,P)## and ##p=p(Q,P)##, which we then substitute into the poisson bracket, or any other function as a matter of fact, and this will naturally satisfy the condition that the numerical value is invariant.
Which is the correct definition of invariance, and if it's that the numerical value doesn't change, why then is this invariance so significant?