- #1
iLIKEstuff
- 25
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So I have a simple/easy to answer question for any physics buffs out there. I think I'm doing something fundamentally flawed.
Can you take the inverse of a divergence? analagous to antiderivative-integral?
e.g., I want to find J from the continuity equation with a known [tex] \rho(\vec{r},t) [/tex]
like
[tex] \frac{\partial \rho}{\partial t} + \nabla \cdot \mathbf{J} = 0[/tex]
so I'm trying to do
[tex] invdiv(\frac{\partial \rho}{\partial t}) = invdiv(- \nabla \cdot \mathbf{J}) [/tex]
where "invdiv" would be some inverse divergence operation.
I think trying to get J this way may be fundamentally flawed. As extra information [tex] \rho(\mathbf{r},t) = -e \delta(x) \delta(y) \delta(z - \frac{\Delta Z}{9}sin(\omega t))[/tex] where e is electron charge. How do you handle the Dirac functions in there?
THanks for the help.
Can you take the inverse of a divergence? analagous to antiderivative-integral?
e.g., I want to find J from the continuity equation with a known [tex] \rho(\vec{r},t) [/tex]
like
[tex] \frac{\partial \rho}{\partial t} + \nabla \cdot \mathbf{J} = 0[/tex]
so I'm trying to do
[tex] invdiv(\frac{\partial \rho}{\partial t}) = invdiv(- \nabla \cdot \mathbf{J}) [/tex]
where "invdiv" would be some inverse divergence operation.
I think trying to get J this way may be fundamentally flawed. As extra information [tex] \rho(\mathbf{r},t) = -e \delta(x) \delta(y) \delta(z - \frac{\Delta Z}{9}sin(\omega t))[/tex] where e is electron charge. How do you handle the Dirac functions in there?
THanks for the help.