Inverse laplace transform without partial fractions

Homework Statement

take inverse laplace of:

6/[s^4(s-2)^2]

6/[s^4(s-2)^2]

The Attempt at a Solution

I used partial fractions. I was wondering if It could be manipulated to where I could use the laplace table?

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vela
Staff Emeritus
Homework Helper
If you don't want to use partial fractions, you could evaluate the Bromwich integral:
$$\frac{1}{2\pi i}\int_{\sigma-i\infty}^{\sigma+i\infty} \frac {6 e^{st}}{s^4(s-2)^2}\,ds$$

LCKurtz
Homework Helper
Gold Member

Homework Statement

take inverse laplace of:

6/[s^4(s-2)^2]

6/[s^4(s-2)^2]

The Attempt at a Solution

I used partial fractions. I was wondering if It could be manipulated to where I could use the laplace table?
You could write it as$$\frac 6 {s^4}\cdot \frac 1 {(s-2)^2}$$inverse both factors using table methods, and take the convolution for your answer. Not sure it would be any easier though.