- #1

victoranderson

- 34

- 0

Please see attached.

I am not sure whether my example of this function is correct.

f(x) = ##sin(\frac{\pi x}{2})##

obviously, f(x) is continuous on [-1,1] and differentiable on (-1,1)

Inverse of f(x) will be ##\frac{2 sin^{-1}x}{\pi} ##

and d/dx (inverse of f(x)) will be ##\frac{2}{π \sqrt{1-x^2}}##

So not differentiable in -1,1 ??

I am not sure whether my example of this function is correct.

f(x) = ##sin(\frac{\pi x}{2})##

obviously, f(x) is continuous on [-1,1] and differentiable on (-1,1)

Inverse of f(x) will be ##\frac{2 sin^{-1}x}{\pi} ##

and d/dx (inverse of f(x)) will be ##\frac{2}{π \sqrt{1-x^2}}##

So not differentiable in -1,1 ??