Inverse of function and its domain/range?

  • Thread starter Thread starter adelaide87
  • Start date Start date
  • Tags Tags
    Function Inverse
Click For Summary

Homework Help Overview

The discussion revolves around finding the inverse of the function f(x) = (3x + 4) / (5 - 2x) and determining the domain and range for both the function and its inverse.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the original function's domain and range, with some questioning the exclusion of specific values. There is an exploration of the inverse function's form and its implications for domain and range.

Discussion Status

Some participants have provided feedback on the inverse function's correctness, while others are seeking clarification on the domain and range of both the original function and its inverse. Multiple interpretations of the range are being explored, indicating an ongoing discussion.

Contextual Notes

There are mentions of specific values that may or may not be included in the domain and range, with participants expressing uncertainty about the implications for the inverse function.

adelaide87
Messages
24
Reaction score
0

Homework Statement



a) find the inverse of f(x)= (3x+4)/(5-2x)
b) state the domain anr rage for both f and f^-1


Homework Equations





The Attempt at a Solution



for f(x)
Domain:x ≠ 5/2, x ∈ R
Range: y ≠ 3/2, y ∈ R

Inverse (my answer):

f^-1(x) = (5y-4)/(3+2y)

I want to check and see if this is correct, and also get some guidance of the domain/range for the inverse?

Thanks!
 
Physics news on Phys.org
how did you get that 3/2 is not in the range?

what about f(0.5833333333)?

f^-1 looks right though.
 
Last edited:
I evaluated the limit from x > inf and a > -infWhen you do that, the result becomes -3/2

(sorry, just realized it wasnt -'ive above. Should be -3/2!)
 
but shouldn't that be missing from the domain of f^-1 ?
The range of f is all of R and the range of f^-1 is also all of R

right?
 
What I've put above is just the domain and range for f(x)

Domain:x ≠ 5/2, x ∈ R
Range: y ≠ -3/2, y ∈ R

--------------------------------------------------------

Its the inverse, f^-1(x), that I need help finding the domain and range for now.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
12
Views
2K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
13
Views
5K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K