- #1

- 1

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My attempt to the solution is not that all impressive. I know i have to use convolution to do it, so far i got this

H(s)= (1/(s^2+9).(1/(s^2+9)^2

- Thread starter capo12
- Start date

- #1

- 1

- 0

My attempt to the solution is not that all impressive. I know i have to use convolution to do it, so far i got this

H(s)= (1/(s^2+9).(1/(s^2+9)^2

- #2

- 135

- 0

\frac{1}{(s^2+9)^2}=\frac{1}{s^2+3^2}\frac{1}{s^2+3^2}[/tex]

Can you make that a convolution of two inverse transforms you already know?

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