Inverse of This Laplace Function

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SUMMARY

The discussion centers on finding the inverse Laplace transform of the function H(s) = 1/(s^2 + 9)^2. The user identifies the need to apply convolution to solve the problem and attempts to express H(s) as a product of known inverse transforms. The key insight is recognizing that H(s) can be represented as the convolution of two transforms, specifically involving the function 1/(s^2 + 3^2).

PREREQUISITES
  • Understanding of Laplace transforms and their properties
  • Familiarity with convolution theorem in Laplace transforms
  • Knowledge of inverse Laplace transforms of standard functions
  • Basic algebraic manipulation of rational functions
NEXT STEPS
  • Study the convolution theorem in detail for Laplace transforms
  • Learn how to compute inverse Laplace transforms of functions like 1/(s^2 + a^2)
  • Explore examples of convolution of inverse transforms
  • Practice solving complex Laplace transform problems using MATLAB or Python
USEFUL FOR

Students and professionals in engineering, mathematics, and physics who are working with Laplace transforms and need to understand convolution techniques for solving differential equations.

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H(s) = 1/(s^2+9)^2

My attempt to the solution is not that all impressive. I know i have to use convolution to do it, so far i got this

H(s)= (1/(s^2+9).(1/(s^2+9)^2
 
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[tex] \frac{1}{(s^2+9)^2}=\frac{1}{s^2+3^2}\frac{1}{s^2+3^2}[/tex]

Can you make that a convolution of two inverse transforms you already know?
 

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