# Inverse of This Laplace Function

1. Nov 29, 2008

### capo12

H(s) = 1/(s^2+9)^2

My attempt to the solution is not that all impressive. I know i have to use convolution to do it, so far i got this

H(s)= (1/(s^2+9).(1/(s^2+9)^2

2. Nov 29, 2008

### jeffreydk

$$\frac{1}{(s^2+9)^2}=\frac{1}{s^2+3^2}\frac{1}{s^2+3^2}$$

Can you make that a convolution of two inverse transforms you already know?