Inverse of This Laplace Function

  • Thread starter capo12
  • Start date
  • #1
1
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H(s) = 1/(s^2+9)^2

My attempt to the solution is not that all impressive. I know i have to use convolution to do it, so far i got this

H(s)= (1/(s^2+9).(1/(s^2+9)^2
 

Answers and Replies

  • #2
135
0
[tex]
\frac{1}{(s^2+9)^2}=\frac{1}{s^2+3^2}\frac{1}{s^2+3^2}[/tex]

Can you make that a convolution of two inverse transforms you already know?
 

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