Inverted Pendulum: Relating Force to Angle/Displacement

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SUMMARY

The discussion focuses on the dynamics of an inverted pendulum, specifically how to relate the applied force to the angle (theta) and displacement of the pendulum's end. The torque generated by the weight at the end of the pendulum is calculated as mgr*cos(theta), where r is the length of the pendulum. To counteract this torque, the minimum force required is mg*cos(theta), assuming the force is applied perpendicularly to the rod. Understanding these relationships is crucial for analyzing the stability and motion of the inverted pendulum.

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Im considering a problem were an inverted pendulum is resting against a ledge an an angle theta from the horizontal. A force is applied to the end causing it to move, This force is dynamic and decrease as the angle increases. The critical point is when the pendulum passes the vertical and cannot return to its resting point falls to the other side.

Does anyone know how i can relate the magnitude of the force to either the angle or displacement of the end of the pendulum?

suggestions welcome.
thanks
 
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The weight at the end of the pendulum produces a torque. This is obviously mgr*cos(theta), where r is the length of the pendulum. To counter this torque, the minimum force needed is mg*cos(theta) if the force is directed perpendicularly to the rod.
 

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