A neon sign is a gas discharge tube in which electrons travelling from the cathode to anode collide with neon atoms in dicharge tube and knocks electrons off of them. As electrons return to the neon ions and drop to lower energy levels, light is given off. How fast would an electron have to be moving to eject an electron from an atom of neon,which has a first ionization energy of 2080KJ per mol. OK, I got 2 set of solutions, buI don't know which one of them is the correct one, maybe neither is correct, too. For solution number 1, I calculate the ionization energy for 1 atom of neon, by dividing 2080 by Avogadro number. Then, I get E. I obtain the mass of 1 atom of neon, by dividing its molar mass by Avogadro number, too. Using E= (1/2)(mv^2), i get the value of v=1.436x10^4 m/s. For solution number 2, i do the same thing, except for the value of m, I substitute in the m for an electron. Finally, I get v=2.754x10^6 m/s. Which one is the correct solution? Or neither? Thanks.